replici la fiecare $f_s$: $X(f) = \sum c_kS(f - kf_s)$ · Nyquist: $f_s \geq 2f_{max}$ · informatia: $[-f_s/2, f_s/2]$
lant A/D: FTJ analog anti-aliasing → esantionare → cuantizare · recuperare: FTJ la $W$
aliasing: $f$ apare la $f - mf_s \in [-f_s/2, f_s/2]$; nu se repara dupa ADC
bandpass: FTB analog, $f_s \geq 2B$, $r = f_c \bmod f_s$: banda $[r - \frac B2, r + \frac B2]$ trebuie in $(0, \frac{f_s}{2})$ (ok) sau $(\frac{f_s}{2}, f_s)$ (inversat); ideal $r = f_s/4$, $f_s = \frac{4f_c}{2m+1}$
inversare → $\times(-1)^n$ (muta cu $f_s/2$)
IQ: $s\,e^{-j2\pi f_ct} = i + jq$, $i = s\cos$, $q = -s\sin$; la $r = f_s/4$: $e^{-j\pi n/2} = [1, -j, -1, j]$ (cos $[1,0,-1,0]$, $-\sin$ $[0,-1,0,1]$)
complex: $f_s' \geq B$ · real: $f_s' \geq 2B$ · decimare: $s_M(n) = s(nM)$, $f_s' = f_s/M$, FTJ inainte